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Earth when the hour angle is-and later when +, therefore to determine the apparent hourly motions at apparent conjunction assume two instants; first the time of true conjunction in right ascension and the 2d + or one hour from the first according to the sign of the hour angle; compute the Parallax in right ascension and declination at these two instants,

Then making

A the Moon's right ascension at 1st instant.

D the Moon's declination at 1st instant.

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a the true hourly motion in right ascension. d=the true hourly motion in declination.

a the apparent hourly motion in right ascension.

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-when proceeding to the north and + when to the south. A the difference of declinations at conjunction.

A' apparent difference of declinations at apparent conjunction when the Moon is N and-when south of the star.

p' the parallax in right ascension at the 1st instant.

=

p":

P=

P =

at the 2d instant. in declination at the 1st instant. at the 2d instant.

t-the time from the true to the apparent conjunction. A+p the apparent right ascension at the 1st instant. A+a+p" 2d instant. aap-p' apparent hourly motion in right ascension similarly.

d'=d+ P'—P'=apparent hourly motion in declination:

The difference of the apparent right ascensions of the Moon and star at the 1st instant will be p', and t the time of the Moon describing this space will be t=P

p' a+p

a

Now 1st instant..+t(+or-according to the sign of the hour angle)=time of apparent conjunction in right ascension. But in the interval t, the Moon's declination will be altered by (d+P-P') t.

Therefore

▲'=▲ + P'' + (d· + P' -P')t=apparent difference of declinations at apparent conjunction in right ascension.

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Let us now suppose the Moon to be stationary and the star to be relatively in motion.

Let N. w. y represeut the Moon's surface; c the centre; a b and be the star's apparent horary motion in right ascension and declination; a e the portion of the orbit described in one hour; cx the difference of apparent declinations at apparent in right ascension, and

cn the nearest approach of the centres. Now c n x and x d a being right angles.

the angle d a x=90-d x a.

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the angle da x (which we will call O) being the inclination of the star's apparent orbit to the circle of declination; to compute it, we have

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And t the time describing x n will be =

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n sin O
a' cos D

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Now the time of apparent d in right ascension + t'

(+ when A' and d' are of like signs and

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when

con

trary) time of nearest approach, or the middle of the occultation.

If y represent the place of Immersion, the time of the star describing n y will be the semi-duration, to determine which we have c y S the Moon's semi-diameter c n = n the nearest approach and by the 47th of the 1st Book of Euclid Vs-n2 n2nys n.s n |

h

a' cos D: 1 :: s+n.s -u: the semi

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Time of nearest approach {

S+= the time of Emersion. -the time of Immersion.

The following example will sufficiently illustrate these observations-

I find from the nautical Almanac that on the 9th June w2 Scorpii will be occulted; the following are the ele

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'dd + P'P' 10. 56. 9+ 31. 29. 733. 4. 1

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+ 0,582 = 34. 9 log t + = 9,764994

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